\(\int \frac {(c+a^2 c x^2)^{5/2} \arctan (a x)^2}{x^2} \, dx\) [328]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F(-2)]
   Mupad [F(-1)]

Optimal result

Integrand size = 24, antiderivative size = 655 \[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {c+a^2 c x^2}}-\frac {4 a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {15 a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (3,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {15 a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (3,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}} \]

[Out]

-1/6*a*c*(a^2*c*x^2+c)^(3/2)*arctan(a*x)+1/4*a^2*c*x*(a^2*c*x^2+c)^(3/2)*arctan(a*x)^2+11/6*a*c^(5/2)*arctanh(
a*x*c^(1/2)/(a^2*c*x^2+c)^(1/2))-15/4*I*a*c^3*arctan((1+I*a*x)/(a^2*x^2+1)^(1/2))*arctan(a*x)^2*(a^2*x^2+1)^(1
/2)/(a^2*c*x^2+c)^(1/2)-4*a*c^3*arctan(a*x)*arctanh((1+I*a*x)^(1/2)/(1-I*a*x)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*
x^2+c)^(1/2)+15/4*I*a*c^3*arctan(a*x)*polylog(2,-I*(1+I*a*x)/(a^2*x^2+1)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*x^2+c
)^(1/2)-15/4*I*a*c^3*arctan(a*x)*polylog(2,I*(1+I*a*x)/(a^2*x^2+1)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*x^2+c)^(1/2
)+2*I*a*c^3*polylog(2,-(1+I*a*x)^(1/2)/(1-I*a*x)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*x^2+c)^(1/2)-2*I*a*c^3*polylo
g(2,(1+I*a*x)^(1/2)/(1-I*a*x)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*x^2+c)^(1/2)-15/4*a*c^3*polylog(3,-I*(1+I*a*x)/(
a^2*x^2+1)^(1/2))*(a^2*x^2+1)^(1/2)/(a^2*c*x^2+c)^(1/2)+15/4*a*c^3*polylog(3,I*(1+I*a*x)/(a^2*x^2+1)^(1/2))*(a
^2*x^2+1)^(1/2)/(a^2*c*x^2+c)^(1/2)+1/12*a^2*c^2*x*(a^2*c*x^2+c)^(1/2)-7/4*a*c^2*arctan(a*x)*(a^2*c*x^2+c)^(1/
2)-c^2*arctan(a*x)^2*(a^2*c*x^2+c)^(1/2)/x+7/8*a^2*c^2*x*arctan(a*x)^2*(a^2*c*x^2+c)^(1/2)

Rubi [A] (verified)

Time = 1.03 (sec) , antiderivative size = 655, normalized size of antiderivative = 1.00, number of steps used = 43, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {5070, 5064, 5078, 5074, 5010, 5008, 4266, 2611, 2320, 6724, 5000, 223, 212, 201} \[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=-\frac {4 a c^3 \sqrt {a^2 x^2+1} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {a^2 c x^2+c}}+\frac {15 i a c^3 \sqrt {a^2 x^2+1} \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )}{4 \sqrt {a^2 c x^2+c}}-\frac {15 i a c^3 \sqrt {a^2 x^2+1} \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )}{4 \sqrt {a^2 c x^2+c}}-\frac {15 a c^3 \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (3,-i e^{i \arctan (a x)}\right )}{4 \sqrt {a^2 c x^2+c}}+\frac {15 a c^3 \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (3,i e^{i \arctan (a x)}\right )}{4 \sqrt {a^2 c x^2+c}}-\frac {15 i a c^3 \sqrt {a^2 x^2+1} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {a^2 c x^2+c}}+\frac {7}{8} a^2 c^2 x \arctan (a x)^2 \sqrt {a^2 c x^2+c}-\frac {c^2 \arctan (a x)^2 \sqrt {a^2 c x^2+c}}{x}-\frac {7}{4} a c^2 \arctan (a x) \sqrt {a^2 c x^2+c}+\frac {1}{4} a^2 c x \arctan (a x)^2 \left (a^2 c x^2+c\right )^{3/2}-\frac {1}{6} a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {a^2 c x^2+c}}\right )+\frac {2 i a c^3 \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (2,-\frac {\sqrt {i a x+1}}{\sqrt {1-i a x}}\right )}{\sqrt {a^2 c x^2+c}}-\frac {2 i a c^3 \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (2,\frac {\sqrt {i a x+1}}{\sqrt {1-i a x}}\right )}{\sqrt {a^2 c x^2+c}}+\frac {1}{12} a^2 c^2 x \sqrt {a^2 c x^2+c} \]

[In]

Int[((c + a^2*c*x^2)^(5/2)*ArcTan[a*x]^2)/x^2,x]

[Out]

(a^2*c^2*x*Sqrt[c + a^2*c*x^2])/12 - (7*a*c^2*Sqrt[c + a^2*c*x^2]*ArcTan[a*x])/4 - (a*c*(c + a^2*c*x^2)^(3/2)*
ArcTan[a*x])/6 - (c^2*Sqrt[c + a^2*c*x^2]*ArcTan[a*x]^2)/x + (7*a^2*c^2*x*Sqrt[c + a^2*c*x^2]*ArcTan[a*x]^2)/8
 + (a^2*c*x*(c + a^2*c*x^2)^(3/2)*ArcTan[a*x]^2)/4 - (((15*I)/4)*a*c^3*Sqrt[1 + a^2*x^2]*ArcTan[E^(I*ArcTan[a*
x])]*ArcTan[a*x]^2)/Sqrt[c + a^2*c*x^2] - (4*a*c^3*Sqrt[1 + a^2*x^2]*ArcTan[a*x]*ArcTanh[Sqrt[1 + I*a*x]/Sqrt[
1 - I*a*x]])/Sqrt[c + a^2*c*x^2] + (11*a*c^(5/2)*ArcTanh[(a*Sqrt[c]*x)/Sqrt[c + a^2*c*x^2]])/6 + (((15*I)/4)*a
*c^3*Sqrt[1 + a^2*x^2]*ArcTan[a*x]*PolyLog[2, (-I)*E^(I*ArcTan[a*x])])/Sqrt[c + a^2*c*x^2] - (((15*I)/4)*a*c^3
*Sqrt[1 + a^2*x^2]*ArcTan[a*x]*PolyLog[2, I*E^(I*ArcTan[a*x])])/Sqrt[c + a^2*c*x^2] + ((2*I)*a*c^3*Sqrt[1 + a^
2*x^2]*PolyLog[2, -(Sqrt[1 + I*a*x]/Sqrt[1 - I*a*x])])/Sqrt[c + a^2*c*x^2] - ((2*I)*a*c^3*Sqrt[1 + a^2*x^2]*Po
lyLog[2, Sqrt[1 + I*a*x]/Sqrt[1 - I*a*x]])/Sqrt[c + a^2*c*x^2] - (15*a*c^3*Sqrt[1 + a^2*x^2]*PolyLog[3, (-I)*E
^(I*ArcTan[a*x])])/(4*Sqrt[c + a^2*c*x^2]) + (15*a*c^3*Sqrt[1 + a^2*x^2]*PolyLog[3, I*E^(I*ArcTan[a*x])])/(4*S
qrt[c + a^2*c*x^2])

Rule 201

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[x*((a + b*x^n)^p/(n*p + 1)), x] + Dist[a*n*(p/(n*p + 1)),
 Int[(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && GtQ[p, 0] && (IntegerQ[2*p] || (EqQ[n, 2
] && IntegerQ[4*p]) || (EqQ[n, 2] && IntegerQ[3*p]) || LtQ[Denominator[p + 1/n], Denominator[p]])

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 223

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 2320

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 2611

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(-(
f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Dist[g*(m/(b*c*n*Log[F])), Int[(f + g*
x)^(m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e, f, g, n}, x] && GtQ[m, 0]

Rule 4266

Int[csc[(e_.) + Pi*(k_.) + (f_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E
^(I*k*Pi)*E^(I*(e + f*x))]/f), x] + (-Dist[d*(m/f), Int[(c + d*x)^(m - 1)*Log[1 - E^(I*k*Pi)*E^(I*(e + f*x))],
 x], x] + Dist[d*(m/f), Int[(c + d*x)^(m - 1)*Log[1 + E^(I*k*Pi)*E^(I*(e + f*x))], x], x]) /; FreeQ[{c, d, e,
f}, x] && IntegerQ[2*k] && IGtQ[m, 0]

Rule 5000

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Simp[(-b)*p*(d + e*x^2)^
q*((a + b*ArcTan[c*x])^(p - 1)/(2*c*q*(2*q + 1))), x] + (Dist[2*d*(q/(2*q + 1)), Int[(d + e*x^2)^(q - 1)*(a +
b*ArcTan[c*x])^p, x], x] + Dist[b^2*d*p*((p - 1)/(2*q*(2*q + 1))), Int[(d + e*x^2)^(q - 1)*(a + b*ArcTan[c*x])
^(p - 2), x], x] + Simp[x*(d + e*x^2)^q*((a + b*ArcTan[c*x])^p/(2*q + 1)), x]) /; FreeQ[{a, b, c, d, e}, x] &&
 EqQ[e, c^2*d] && GtQ[q, 0] && GtQ[p, 1]

Rule 5008

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Dist[1/(c*Sqrt[d]), Subst
[Int[(a + b*x)^p*Sec[x], x], x, ArcTan[c*x]], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && IGtQ[p, 0] &
& GtQ[d, 0]

Rule 5010

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Dist[Sqrt[1 + c^2*x^2]/Sq
rt[d + e*x^2], Int[(a + b*ArcTan[c*x])^p/Sqrt[1 + c^2*x^2], x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*
d] && IGtQ[p, 0] &&  !GtQ[d, 0]

Rule 5064

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Simp
[(f*x)^(m + 1)*(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^p/(d*f*(m + 1))), x] - Dist[b*c*(p/(f*(m + 1))), Int[(
f*x)^(m + 1)*(d + e*x^2)^q*(a + b*ArcTan[c*x])^(p - 1), x], x] /; FreeQ[{a, b, c, d, e, f, m, q}, x] && EqQ[e,
 c^2*d] && EqQ[m + 2*q + 3, 0] && GtQ[p, 0] && NeQ[m, -1]

Rule 5070

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Dist[
d, Int[(f*x)^m*(d + e*x^2)^(q - 1)*(a + b*ArcTan[c*x])^p, x], x] + Dist[c^2*(d/f^2), Int[(f*x)^(m + 2)*(d + e*
x^2)^(q - 1)*(a + b*ArcTan[c*x])^p, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[e, c^2*d] && GtQ[q, 0] &&
 IGtQ[p, 0] && (RationalQ[m] || (EqQ[p, 1] && IntegerQ[q]))

Rule 5074

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))/((x_)*Sqrt[(d_) + (e_.)*(x_)^2]), x_Symbol] :> Simp[(-2/Sqrt[d])*(a + b
*ArcTan[c*x])*ArcTanh[Sqrt[1 + I*c*x]/Sqrt[1 - I*c*x]], x] + (Simp[I*(b/Sqrt[d])*PolyLog[2, -Sqrt[1 + I*c*x]/S
qrt[1 - I*c*x]], x] - Simp[I*(b/Sqrt[d])*PolyLog[2, Sqrt[1 + I*c*x]/Sqrt[1 - I*c*x]], x]) /; FreeQ[{a, b, c, d
, e}, x] && EqQ[e, c^2*d] && GtQ[d, 0]

Rule 5078

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*Sqrt[(d_) + (e_.)*(x_)^2]), x_Symbol] :> Dist[Sqrt[1 + c^2*
x^2]/Sqrt[d + e*x^2], Int[(a + b*ArcTan[c*x])^p/(x*Sqrt[1 + c^2*x^2]), x], x] /; FreeQ[{a, b, c, d, e}, x] &&
EqQ[e, c^2*d] && IGtQ[p, 0] &&  !GtQ[d, 0]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps \begin{align*} \text {integral}& = c \int \frac {\left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2}{x^2} \, dx+\left (a^2 c\right ) \int \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2 \, dx \\ & = -\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2+c^2 \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)^2}{x^2} \, dx+\frac {1}{6} \left (a^2 c^2\right ) \int \sqrt {c+a^2 c x^2} \, dx+\frac {1}{4} \left (3 a^2 c^2\right ) \int \sqrt {c+a^2 c x^2} \arctan (a x)^2 \, dx+\left (a^2 c^2\right ) \int \sqrt {c+a^2 c x^2} \arctan (a x)^2 \, dx \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2+c^3 \int \frac {\arctan (a x)^2}{x^2 \sqrt {c+a^2 c x^2}} \, dx+\frac {1}{12} \left (a^2 c^3\right ) \int \frac {1}{\sqrt {c+a^2 c x^2}} \, dx+\frac {1}{8} \left (3 a^2 c^3\right ) \int \frac {\arctan (a x)^2}{\sqrt {c+a^2 c x^2}} \, dx+\frac {1}{2} \left (a^2 c^3\right ) \int \frac {\arctan (a x)^2}{\sqrt {c+a^2 c x^2}} \, dx+\frac {1}{4} \left (3 a^2 c^3\right ) \int \frac {1}{\sqrt {c+a^2 c x^2}} \, dx+\left (a^2 c^3\right ) \int \frac {1}{\sqrt {c+a^2 c x^2}} \, dx+\left (a^2 c^3\right ) \int \frac {\arctan (a x)^2}{\sqrt {c+a^2 c x^2}} \, dx \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2+\left (2 a c^3\right ) \int \frac {\arctan (a x)}{x \sqrt {c+a^2 c x^2}} \, dx+\frac {1}{12} \left (a^2 c^3\right ) \text {Subst}\left (\int \frac {1}{1-a^2 c x^2} \, dx,x,\frac {x}{\sqrt {c+a^2 c x^2}}\right )+\frac {1}{4} \left (3 a^2 c^3\right ) \text {Subst}\left (\int \frac {1}{1-a^2 c x^2} \, dx,x,\frac {x}{\sqrt {c+a^2 c x^2}}\right )+\left (a^2 c^3\right ) \text {Subst}\left (\int \frac {1}{1-a^2 c x^2} \, dx,x,\frac {x}{\sqrt {c+a^2 c x^2}}\right )+\frac {\left (3 a^2 c^3 \sqrt {1+a^2 x^2}\right ) \int \frac {\arctan (a x)^2}{\sqrt {1+a^2 x^2}} \, dx}{8 \sqrt {c+a^2 c x^2}}+\frac {\left (a^2 c^3 \sqrt {1+a^2 x^2}\right ) \int \frac {\arctan (a x)^2}{\sqrt {1+a^2 x^2}} \, dx}{2 \sqrt {c+a^2 c x^2}}+\frac {\left (a^2 c^3 \sqrt {1+a^2 x^2}\right ) \int \frac {\arctan (a x)^2}{\sqrt {1+a^2 x^2}} \, dx}{\sqrt {c+a^2 c x^2}} \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {\left (3 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x^2 \sec (x) \, dx,x,\arctan (a x)\right )}{8 \sqrt {c+a^2 c x^2}}+\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x^2 \sec (x) \, dx,x,\arctan (a x)\right )}{2 \sqrt {c+a^2 c x^2}}+\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x^2 \sec (x) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (2 a c^3 \sqrt {1+a^2 x^2}\right ) \int \frac {\arctan (a x)}{x \sqrt {1+a^2 x^2}} \, dx}{\sqrt {c+a^2 c x^2}} \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {c+a^2 c x^2}}-\frac {4 a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (3 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {\left (3 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1+i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1+i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (2 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (2 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int x \log \left (1+i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}} \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {c+a^2 c x^2}}-\frac {4 a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (3 i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {\left (3 i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {\left (i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (2 i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,-i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (2 i a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \operatorname {PolyLog}\left (2,i e^{i x}\right ) \, dx,x,\arctan (a x)\right )}{\sqrt {c+a^2 c x^2}} \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {c+a^2 c x^2}}-\frac {4 a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (3 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,-i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {\left (3 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,-i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{\sqrt {c+a^2 c x^2}}-\frac {\left (2 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,-i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{\sqrt {c+a^2 c x^2}}+\frac {\left (2 a c^3 \sqrt {1+a^2 x^2}\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,i x)}{x} \, dx,x,e^{i \arctan (a x)}\right )}{\sqrt {c+a^2 c x^2}} \\ & = \frac {1}{12} a^2 c^2 x \sqrt {c+a^2 c x^2}-\frac {7}{4} a c^2 \sqrt {c+a^2 c x^2} \arctan (a x)-\frac {1}{6} a c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)-\frac {c^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2}{x}+\frac {7}{8} a^2 c^2 x \sqrt {c+a^2 c x^2} \arctan (a x)^2+\frac {1}{4} a^2 c x \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)^2-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2}{4 \sqrt {c+a^2 c x^2}}-\frac {4 a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \text {arctanh}\left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {11}{6} a c^{5/2} \text {arctanh}\left (\frac {a \sqrt {c} x}{\sqrt {c+a^2 c x^2}}\right )+\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}-\frac {15 i a c^3 \sqrt {1+a^2 x^2} \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {2 i a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {15 a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (3,-i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}}+\frac {15 a c^3 \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (3,i e^{i \arctan (a x)}\right )}{4 \sqrt {c+a^2 c x^2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 1.61 (sec) , antiderivative size = 626, normalized size of antiderivative = 0.96 \[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\frac {c^2 \sqrt {c+a^2 c x^2} \left (2 a^2 x^2 \sqrt {1+a^2 x^2}+2 a^4 x^4 \sqrt {1+a^2 x^2}-190 a x \sqrt {1+a^2 x^2} \arctan (a x)+2 a^3 x^3 \sqrt {1+a^2 x^2} \arctan (a x)-96 \sqrt {1+a^2 x^2} \arctan (a x)^2+117 a^2 x^2 \sqrt {1+a^2 x^2} \arctan (a x)^2+21 a^4 x^4 \sqrt {1+a^2 x^2} \arctan (a x)^2-168 i a x \arctan \left (e^{i \arctan (a x)}\right ) \arctan (a x)^2+176 a x \text {arctanh}\left (\frac {a x}{\sqrt {1+a^2 x^2}}\right )+6 a x \arctan (a x) \cos (3 \arctan (a x))+12 a^3 x^3 \arctan (a x) \cos (3 \arctan (a x))+6 a^5 x^5 \arctan (a x) \cos (3 \arctan (a x))+192 a x \arctan (a x) \log \left (1-e^{i \arctan (a x)}\right )+96 a x \arctan (a x)^2 \log \left (1-i e^{i \arctan (a x)}\right )-96 a x \arctan (a x)^2 \log \left (1+i e^{i \arctan (a x)}\right )-192 a x \arctan (a x) \log \left (1+e^{i \arctan (a x)}\right )+192 i a x \operatorname {PolyLog}\left (2,-e^{i \arctan (a x)}\right )+360 i a x \arctan (a x) \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )-360 i a x \arctan (a x) \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )-192 i a x \operatorname {PolyLog}\left (2,e^{i \arctan (a x)}\right )-360 a x \operatorname {PolyLog}\left (3,-i e^{i \arctan (a x)}\right )+360 a x \operatorname {PolyLog}\left (3,i e^{i \arctan (a x)}\right )+2 a x \sin (3 \arctan (a x))+4 a^3 x^3 \sin (3 \arctan (a x))+2 a^5 x^5 \sin (3 \arctan (a x))-3 a x \arctan (a x)^2 \sin (3 \arctan (a x))-6 a^3 x^3 \arctan (a x)^2 \sin (3 \arctan (a x))-3 a^5 x^5 \arctan (a x)^2 \sin (3 \arctan (a x))\right )}{96 x \sqrt {1+a^2 x^2}} \]

[In]

Integrate[((c + a^2*c*x^2)^(5/2)*ArcTan[a*x]^2)/x^2,x]

[Out]

(c^2*Sqrt[c + a^2*c*x^2]*(2*a^2*x^2*Sqrt[1 + a^2*x^2] + 2*a^4*x^4*Sqrt[1 + a^2*x^2] - 190*a*x*Sqrt[1 + a^2*x^2
]*ArcTan[a*x] + 2*a^3*x^3*Sqrt[1 + a^2*x^2]*ArcTan[a*x] - 96*Sqrt[1 + a^2*x^2]*ArcTan[a*x]^2 + 117*a^2*x^2*Sqr
t[1 + a^2*x^2]*ArcTan[a*x]^2 + 21*a^4*x^4*Sqrt[1 + a^2*x^2]*ArcTan[a*x]^2 - (168*I)*a*x*ArcTan[E^(I*ArcTan[a*x
])]*ArcTan[a*x]^2 + 176*a*x*ArcTanh[(a*x)/Sqrt[1 + a^2*x^2]] + 6*a*x*ArcTan[a*x]*Cos[3*ArcTan[a*x]] + 12*a^3*x
^3*ArcTan[a*x]*Cos[3*ArcTan[a*x]] + 6*a^5*x^5*ArcTan[a*x]*Cos[3*ArcTan[a*x]] + 192*a*x*ArcTan[a*x]*Log[1 - E^(
I*ArcTan[a*x])] + 96*a*x*ArcTan[a*x]^2*Log[1 - I*E^(I*ArcTan[a*x])] - 96*a*x*ArcTan[a*x]^2*Log[1 + I*E^(I*ArcT
an[a*x])] - 192*a*x*ArcTan[a*x]*Log[1 + E^(I*ArcTan[a*x])] + (192*I)*a*x*PolyLog[2, -E^(I*ArcTan[a*x])] + (360
*I)*a*x*ArcTan[a*x]*PolyLog[2, (-I)*E^(I*ArcTan[a*x])] - (360*I)*a*x*ArcTan[a*x]*PolyLog[2, I*E^(I*ArcTan[a*x]
)] - (192*I)*a*x*PolyLog[2, E^(I*ArcTan[a*x])] - 360*a*x*PolyLog[3, (-I)*E^(I*ArcTan[a*x])] + 360*a*x*PolyLog[
3, I*E^(I*ArcTan[a*x])] + 2*a*x*Sin[3*ArcTan[a*x]] + 4*a^3*x^3*Sin[3*ArcTan[a*x]] + 2*a^5*x^5*Sin[3*ArcTan[a*x
]] - 3*a*x*ArcTan[a*x]^2*Sin[3*ArcTan[a*x]] - 6*a^3*x^3*ArcTan[a*x]^2*Sin[3*ArcTan[a*x]] - 3*a^5*x^5*ArcTan[a*
x]^2*Sin[3*ArcTan[a*x]]))/(96*x*Sqrt[1 + a^2*x^2])

Maple [A] (verified)

Time = 2.93 (sec) , antiderivative size = 399, normalized size of antiderivative = 0.61

method result size
default \(\frac {c^{2} \sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (6 a^{4} \arctan \left (a x \right )^{2} x^{4}-4 \arctan \left (a x \right ) x^{3} a^{3}+27 x^{2} \arctan \left (a x \right )^{2} a^{2}+2 a^{2} x^{2}-46 x \arctan \left (a x \right ) a -24 \arctan \left (a x \right )^{2}\right )}{24 x}+\frac {i c^{2} a \sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (45 i \arctan \left (a x \right )^{2} \ln \left (1+\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )-45 i \arctan \left (a x \right )^{2} \ln \left (1-\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )+48 i \arctan \left (a x \right ) \ln \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}+1\right )+90 \arctan \left (a x \right ) \operatorname {polylog}\left (2, -\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )-90 \arctan \left (a x \right ) \operatorname {polylog}\left (2, \frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )+90 i \operatorname {polylog}\left (3, -\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )-90 i \operatorname {polylog}\left (3, \frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )-88 \arctan \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}\right )+48 \operatorname {dilog}\left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}+1\right )+48 \operatorname {dilog}\left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}\right )\right )}{24 \sqrt {a^{2} x^{2}+1}}\) \(399\)

[In]

int((a^2*c*x^2+c)^(5/2)*arctan(a*x)^2/x^2,x,method=_RETURNVERBOSE)

[Out]

1/24*c^2*(c*(a*x-I)*(I+a*x))^(1/2)*(6*a^4*arctan(a*x)^2*x^4-4*arctan(a*x)*x^3*a^3+27*x^2*arctan(a*x)^2*a^2+2*a
^2*x^2-46*x*arctan(a*x)*a-24*arctan(a*x)^2)/x+1/24*I*c^2*a*(c*(a*x-I)*(I+a*x))^(1/2)*(45*I*arctan(a*x)^2*ln(1+
I*(1+I*a*x)/(a^2*x^2+1)^(1/2))-45*I*arctan(a*x)^2*ln(1-I*(1+I*a*x)/(a^2*x^2+1)^(1/2))+48*I*arctan(a*x)*ln((1+I
*a*x)/(a^2*x^2+1)^(1/2)+1)+90*arctan(a*x)*polylog(2,-I*(1+I*a*x)/(a^2*x^2+1)^(1/2))-90*arctan(a*x)*polylog(2,I
*(1+I*a*x)/(a^2*x^2+1)^(1/2))+90*I*polylog(3,-I*(1+I*a*x)/(a^2*x^2+1)^(1/2))-90*I*polylog(3,I*(1+I*a*x)/(a^2*x
^2+1)^(1/2))-88*arctan((1+I*a*x)/(a^2*x^2+1)^(1/2))+48*dilog((1+I*a*x)/(a^2*x^2+1)^(1/2)+1)+48*dilog((1+I*a*x)
/(a^2*x^2+1)^(1/2)))/(a^2*x^2+1)^(1/2)

Fricas [F]

\[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\int { \frac {{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} \arctan \left (a x\right )^{2}}{x^{2}} \,d x } \]

[In]

integrate((a^2*c*x^2+c)^(5/2)*arctan(a*x)^2/x^2,x, algorithm="fricas")

[Out]

integral((a^4*c^2*x^4 + 2*a^2*c^2*x^2 + c^2)*sqrt(a^2*c*x^2 + c)*arctan(a*x)^2/x^2, x)

Sympy [F]

\[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\int \frac {\left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {5}{2}} \operatorname {atan}^{2}{\left (a x \right )}}{x^{2}}\, dx \]

[In]

integrate((a**2*c*x**2+c)**(5/2)*atan(a*x)**2/x**2,x)

[Out]

Integral((c*(a**2*x**2 + 1))**(5/2)*atan(a*x)**2/x**2, x)

Maxima [F]

\[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\int { \frac {{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} \arctan \left (a x\right )^{2}}{x^{2}} \,d x } \]

[In]

integrate((a^2*c*x^2+c)^(5/2)*arctan(a*x)^2/x^2,x, algorithm="maxima")

[Out]

integrate((a^2*c*x^2 + c)^(5/2)*arctan(a*x)^2/x^2, x)

Giac [F(-2)]

Exception generated. \[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((a^2*c*x^2+c)^(5/2)*arctan(a*x)^2/x^2,x, algorithm="giac")

[Out]

Exception raised: TypeError >> an error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2}{x^2} \, dx=\int \frac {{\mathrm {atan}\left (a\,x\right )}^2\,{\left (c\,a^2\,x^2+c\right )}^{5/2}}{x^2} \,d x \]

[In]

int((atan(a*x)^2*(c + a^2*c*x^2)^(5/2))/x^2,x)

[Out]

int((atan(a*x)^2*(c + a^2*c*x^2)^(5/2))/x^2, x)